In order to check whether a number is a perfect cube or not, we find its prime factors and group together triplets of the prime factors. If no factor is left out then the number is a perfect cube. However if one of the prime factors is a single factor or a double factor then the number is not a perfect cube.
However, factorization method is time consuming and there is an interesting shortcut, using which we can easily and quickly check if the given number is a perfect cube or not.
Another Method is of the digital SUM.
Digital sum of a number is calculated as:
for numbers 1 to 9 digital sum is same as the number itself.
For Example :- Digital sum of 4 is 4,digital sum of 2 is 2.
For numbers which are greater than 2 digits,it can be calculated as:-
Digital sum of 123 = 1+2+3 = 6
Digital sum of 456= 4+5+6= 15 = 1+5 =6
Note that we always have to find the digital sum as a single digit number, if the sum of the individual numbers comes up to be greater than 10, we need to add the digits again in order to obtain a single digit number as shown in the Example(Digital sum of 456).
Digital root is also same as the Digital sum.
| Number | Cube | Digital Root of the cube |
| 1 | 1 | 1 |
| 2 | 8 | 8 |
| 3 | 27 | 9 (or 0) |
| 4 | 64 | 1 |
| 5 | 125 | 8 |
| 6 | 216 | 9 (or 0) |
| 7 | 343 | 1 |
| 8 | 512 | 8 |
| 9 | 729 | 9 (or 0) |
Notice, the digital root of a perfect cube is 1, 8 or 9 (0). However, the converse is not always true.
So, all perfect cubes must have digital root 1, 8 or 9 (0). Moreover, the digital root of any number’s cube can be determined by the remainder the number gives when divided by 3:
- If the number is divisible by 3, its cube has digital root 9;
- If it has a remainder of 1 when divided by 3, its cube has digital root 1;
- If it has a remainder of 2 when divided by 3, its cube has digital root 8.